I made a new rule to allow tcp port 23 traffic outbound. But I am unable to connect to the external ftp server on port 23. In the log files I see the following Ports 20 - 24 are allowed out. No rule for inbound.
" deny out eth 1 48 tcp 20 127 192... 156.12... 8261 3094 syn (default)"
How do I read the above line? What dose the 48 tcp 20 represent and also the 8261 and 3064?
Thanks
what version of WatchGuard?
Version x20e 8.2.1
If you have an X20, then it's new enough that you should also have support - just call them directly.
FTP requires 2 ports, not just one.
If you look at the DENY line:
DENY, OUT, ETH x, AAA, TCP, BBB, CCC, IP.AD.D.RES1, IP.AD.D.RES2, DDDD, EEEE
the EEEE is the port that's being rejected, DDDDD is the source port that is trying to get out to port EEEE (you can ignore DDDD).
SYN DEFAULT means that the default firewall rules are blocking outbound port 3094 - the port you're trying to use to FTP too.
Based on your post, it appears you are trying to use port 3094 for FTP and not 23.
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