My logic in asking would be the same as my friend asking me how much my cellphone cost. I could still quote the price even if I had no intention of selling it to him.
They all told me exactly the same thing. If they told me the price, they would be breaking their legal agreement with the manufacturer.
So, one thing I've learned here is that Bosch sure knows how to lock up a market. I'm pretty sure I will have a source by tomorrow though, as I have a few leads pending from my phone calls.
Hi, What if the new board blows up when replaced? Are planing to protect it some how from that occuring? BTW, looking at arrow marking on diode can yu tell which direction current electron or current flows? Can you tell which lead is cathode or anode?
Hi, You should. That Omron relay contats can be open or closed. Is it NO or NC relay? Is the coil good? Have you metered them out? What is the findings? Did you looked up the specs. of that very common relay?
Thanks for that advice. The sticky tape was covering the traces:
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So, following your advice, I peeled it mostly off, and looked with a magnifying glass as you had suggested:
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The 1,000uF 35V capacitor leads are burnt a bit, but, it could have been a replacement cap for all I know, as the cap is not shorted nor is it an open (it's about 350 ohms steady).
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However, the fact is that this sequence shows *something* is wrong with that D135A battery-protection board:
That's why I only want to spend the $104 to replace it. It *does* have overload circuit protection besides.
I've done plenty of smoke tests in my life. This will be one of them.
Heh heh ... here is a board I built many years ago to test impedence (j omega stuff). I wired a diode to house current! You'll notice the diodes. Particularly, you'll notice that the nichrome wire resistor has the same impedance as the the capacitor. (I couldn't find an inductor of a large enough size.) FRONT:
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BACK:
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Also notice this circuit, where I used 555 timers (I think that's what I used), way back in the 80's, to measure capacitance and resistance simply by counting the flash rate ... FRONT:
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BACK:
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I did those circuits in the early 80's but, of course I know about the shape of the diode curve and which is the anode and which is the cathode.
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Everyone knows this basic stuff... even we accountants.
Before you start pratting around checking diodes, capacitors and the like you should disconnect all the external wiring to the circuit board and power the board up on its own to verify that the field wiring or expansion modules are not the cause of the problem
I hope that you realize that you are not getting a reading off of the capacitor. Most likely that is the resistance of the other components on the board.
Use the meter test lead (red) to touch the red battery lead to the output terminal briefly. You should hear the relay pull in. Then the power terminal should be at 12 volts. This board depends on AC power being applied to the alarm unit and some battery charging current needs to be available to arm the battery protection board.
Hi, You checked the state of that Omron relay? Is it it NC or NO relay. Is the contacts closed now or open, is the coil OK? Diode, and Zener... If you are going after ICs, Huntron tracker comes handy.
I used to use a capacitance meter (I forget what we called them way back in the 80s in one of my lab classes), so, I'm familiar with the fact that it's hard to measure capacitance.
However, I did think (errantly perhaps) that the capacitor would show as a short or as an open if it were "blown".
Since it showed with resistance, I wasn't sure, what I was reading. I *did* expect the voltage to climb slowly, since the meter would have been supplying charge to the capacitor's plates; so, the fact that the resistance was steady should have been a good datapoint.
What I will likely do is take a trip to RadioShack and buy a 1,000 uF 35V electrolytic of a similar size and see if I can wire it back up.
I wanted to first draw the circuit so that I could figure out how to test it though.
So, thanks for pointing out the faux pas in my measurement. I appreciate the correction.
Just bump it with the 12 volts from the battery. That will pull in the relay and latch the output. When the voltage falls below the 9 volt limit, the relay will drop out and disconnect the battery completely.
Just for the fun of it when you go the RS, you might pick up an in line fuse (3 amp or so) and put it in the red battery lead. that will keep the fire from starting. :) Get yourself a supply of fuses just in case. I don't see any fuses on the boards at all.
When you get this working, next thing to do is disconnect all the other panels from the main unit. Tag all the wires so you know where they go. That way, you can narrow down any power issues to just the main board.
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