CM11A hangup: Any better products?

Aug 15, 2005 46 Replies

Hello Dan,

It could be. However, every aligment procedure in production is usually a significant cost contributor. Even in China.

IIUC it outputs to TMR0 reg which indeed isn't so cool. But look at Figure 6-6. Maybe there is a way to pipe it through the WDT path. Unless PSA turns off the WDT Time-Out mux or that signal cannot go anywhere. This doesn't seem to be a very versatile uC. Or as they say in the UK, it doesn't float my boat.

If it can't do all that maybe there is a better uC for X-10 than this one, at similar cost. Quite frankly it is the first uC I come across that seems to be unable to do PWM. Even ye olde C51 could do that.

Regards, Joerg

formatting link

Hello Dave,

I believe you mean the LC tank circuit. Yes, it needs aligment. But it is only a peaking operation where all you need is level metering. A circuit that is in an oscillator requires a frequency counter which is more expensive in production. Assembling a diode concoction on the pogo pins of a production tester is easy if it can't digest 120kHz directly. However, measuring a frequency isn't possible with cheaper testers.

Regards, Joerg

formatting link

Hello Dave,

No, I didn't say that. They will have to have a frequency adjustment procedure at the end of production. That increases cost. If there was a resonator or crystal they wouldn't have to incur that cost.

WRT to alignment I wasn't too impressed with the "precision" of aligment on some of the receivers. As I said earlier, one wouldn't work until after I aligned it myself. Another that occasionally missed a command became much more reliable after aligment.

Regards, Joerg

formatting link

Hello Dave,

Which fantastical procedure? The aligment of the receiver LC circuit? All I can say is that the non-working module worked after that and another one became reliable. That's good enough for me.

Regards, Joerg

formatting link

Join the Discussion

Have something to add? Share your thoughts — no account required.

Didn't find your answer?

Ask the community — no account required