IP route inside 1812 router

Dear all,

I inherited a 1812 router where this route is defined:

ip route 1.2.3.4 255.255.255.255 FastEthernet0 5.6.7.8 name X

where the ip address of FastEthernet0 is defined as 5.6.7.9 ##

How do I have to interpret this configuration?

Many thanks in advance! RB

Reply to
RBläs
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1.2.3.4 255.255.255.255 is the one host 1.2.3.4, so this is a route statement that applies to packets with the single destination host 1.2.3.4.

FastEthernet0 is the interface that the packet is to be sent to.

5.6.7.8 is the IP address of the next hop that the router is to use for the routed packet. You have indicated that the ip address of FastEthernet0 is 5.6.7.9 so likely 5.6.7.8 is the ip address of the ISP's router at the far end of the FastEthernet0 link.
Reply to
Walter Roberson

Thank you, Walter By the way there is also a line in the config file:

resource policy

And the meaning is??????

RB

Reply to
RBläs

Sorry, I have not encountered that one before, and I am encountering too many hits on cisco's site to track down to the most likely.

Is "resource policy" proceeded by "event"?

Do you have the Embedded Resource Policy Manager?

Reply to
Walter Roberson

You can just ignore this command line.

It is, as Walter suggested it might be, for the new Embedded Resource Manager.

Reply to
Merv

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