All, I need some help understanding how volume control impedance calculates into the load seen by the amplifier. Here is my scenario, using just one amp channel for illustration purposes:
I have an amp rated to drive loads from 6 to 16 ohms ... ideally, I would like to present the amp with an 8 ohm load.
I have three, 8 ohm speakers, all with home runs back to the amp. When connected in parallel, they will provide this channel with a load of 2 2/3 ohms (1/Rt = 1/8 + 1/8 + 1/8), which is clearly too low.
This is where I start to get a little fuzzy about how the volume control impedance works ... I know need to create another 6 ohms of impedance to bring the total impedance for this channel to just over 8 ohms, but here are my questions:1) Are I seeing this correctly? If so, I have not been able to identify any volume controls which would create the proper "make-up" impedance. Your suggestions are welcome. 2) Ideally, I'd like to have a volume control with an "off" setting. In this case, I assume that there might be a make-break switch which removes the speaker from the circuit and adds the additional impedance needed to replace the speaker ... is this correct?
Thanks for the education,