I would like to connect a PC to my network with IP address 192.168.1.54/27 By AND-ing 54 with 224 the subnet IP is 192.168.1.32 and the host IP range is 192.168.1.33 to 192.168.1.62. Technically, I could assign to my PC the address 192.168.1.54 , because 54 lives on the IP host range (33-62) of the subnet. However, 192.168.1.54 is the IP address of the network. Isn't there a conflict of IP addresses?
What did I do/understand wrong, please?
Thanks in advance for your help!
new guy :)
DHCP "assign" IP address at any host but you can modify the rules to obtain the same address ;)
What do you mean by , "...192.168.1.54 is the IP address of the network" ? Are you saying 192.168.1.54 is assigned to a host/interface on your network already? For network 192.168.1.32/27, 192.168.1.32 is the subnet address as you stated the broadcast address is 192.168.1.63. so valid host addresses are of course from .33 to .62 as you have stated. 192.168.1.54 is a valid host address for network 192.68.1.32/27. The next subnet would be
192.168.1.64/27 host addresses of .65 to .94. So again, What do you mean by , "...192.168.1.54 is the IP address of the network" ?
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