Do any of you experts know what our theoretical max throughput is for 46 byte payload over the 2Mb Frame MPLS service? I'm getting 1922 K at 4807 pps so I think my FR header is 4 bytes - is this correct ?
1922000 / 4807 = 399 bit frame = 50 byte frame
50 - 46 = 4 byte header
Also is there any formulas that will show me what my theoretical max throughput for a given bandwidth and given packet size
Many thanks
Chet