Passed INTRO on to ICND

I have already passed the Cisco 640-821 CCNA INTRO, I was just wondering for anyone else who took the path of Intro and ICND how hard the ICND is compared to the intro?

Thanks

Reply to
BMoore
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Good question,

I have my ICND booked for next week...

BMoore wrote:

Reply to
Brad

I passed the ICND yesterday with 95%

I'd say it was slightly more difficult than the INTRO, but not much. The labs were easier than I was expecting, and I didn't have any problems with time - I finished 20 minutes early.

BMoore wrote:

Reply to
Brad

Just taken the exam and missed narrowly. To be frank it may as well have been called the subnet exam. About 90% of the questions were on subnetting and mixed in with other subjects. In fact the config answers could have been gleaned from the IP addressing. I found the simulation question impossible at the time (although I now know what it is - I think!).

I had NO or very few questions on ISDN, WANs, Frame Relay, routing theory, VLANs, the configurations all had IP addressing calculations mixed in. I have studied for this exam for the past two months and I really knew my stuff regarding theory and commands. Unfortunately the exam was MASSIVELY skewed towards addressing (a problem I have now resolved in my revision). Also the Richard Deal book is excellent but his practice exam questions are far too soft to prepare you adequately - be warned.

Looking forward to the resit - and possibly getting a better balance of questions.

K.

Thanks

Reply to
Kendo Nagasaki

Yea i went to

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I also bough the Wendell odem INTRO book from Cisco Press it came w/ simulation Software. The book was only 25 bucks, in my opinion was well worth it. I recieved the book in 3 days. However I have since ordered the ICND book by wendell odem and it has been a week and a half and i have not recieved it.

Anyhow, good luck on your next try.

Reply to
BMoore

I was expecting a lot of subnet questions and was fairly well prepared. One thing that I found that helped a lot was writing down a table with the magic number for each mask/# of bits.

# bits mask magic number

1 128 128 2 192 64 3 224 32 4 240 16 5 248 8 6 252 4 7 254 2 8 255 1

I also wrote down multiples of 16 upto 256. ie.

16 32 48 64 96 .. 176 192 208 224 240 256

The reason I wrote down the multiples of 16 was because I found that most 'hard' subnet questions were a .240, /20 or /28 network.

So if you get asked if 192.168.1.239 is a valid host in a /28 network, you can look up and see that 239 is 1 less than 240, so it's a broadcast address.

Or if your asked if 192.168.1.173/28 and 192.168.1.178/28 are in the same subnet, you can see straight away that they are not.

If asked about a .224 or .192 network, then you can just look at every

2nd or 4th number in the list.

Kendo Nagasaki wrote:

Reply to
Brad

Thanks Brad excellent stuff.

In the magic number table what I found helps me is writing how many hosts and subnets are in each mask underneath so my table looks like :-

MASK 128 192 224 240 248 252 254 255 VALUE 128 64 32 16 8 4 2 1 SUBNETS 0 2 6 14 30 62 126 254 HOSTS 126 62 30 14 6 2 0 0

To remember how many subnets and hosts I put a the 14 value (16 minus network and b/c address) in the 240 mask and can work out the rest from there and each side mirrors the other. e.g. 6 subnets in 224 and 6 hosts in

248. So things become realy easy when I'm asked in (practice) questions how many hosts in a 252 mask etc. However I'm going to add the 16 multiples table as you suggest, the thing I forgot to mention in my original post that basically I ran out of time. These subnets really need to be solved within 77 seconds (not that I've worked it out ;-)) to leave 10 minutes for the simulation question which I bombed on last time coz I ran out of time. These tables can be written out before the exam clock starts ticking.

If BMoore is interested and still out there the Wendell Odell ICND book in PDF can be found here for download

formatting link
There are no practice questions from the CD or anything else from the CD for that matter, just the PDF (disclaimer - this isn't my site).

K.

# bits mask magic number

1 128 128 2 192 64 3 224 32 4 240 16 5 248 8 6 252 4 7 254 2 8 255 1

I also wrote down multiples of 16 upto 256. ie.

16 32 48 64 96 .. 176 192 208 224 240 256

The reason I wrote down the multiples of 16 was because I found that most 'hard' subnet questions were a .240, /20 or /28 network.

So if you get asked if 192.168.1.239 is a valid host in a /28 network, you can look up and see that 239 is 1 less than 240, so it's a broadcast address.

Or if your asked if 192.168.1.173/28 and 192.168.1.178/28 are in the same subnet, you can see straight away that they are not.

If asked about a .224 or .192 network, then you can just look at every

2nd or 4th number in the list.

Kendo Nagasaki wrote:

Reply to
Kendo Nagasaki

The ICND is of course by Wendell Odom.

In the magic number table what I found helps me is writing how many hosts and subnets are in each mask underneath so my table looks like :-

MASK 128 192 224 240 248 252 254 255 VALUE 128 64 32 16 8 4 2 1 SUBNETS 0 2 6 14 30 62 126 254 HOSTS 126 62 30 14 6 2 0 0

To remember how many subnets and hosts I put a the 14 value (16 minus network and b/c address) in the 240 mask and can work out the rest from there and each side mirrors the other. e.g. 6 subnets in 224 and 6 hosts in

248. So things become realy easy when I'm asked in (practice) questions how many hosts in a 252 mask etc. However I'm going to add the 16 multiples table as you suggest, the thing I forgot to mention in my original post that basically I ran out of time. These subnets really need to be solved within 77 seconds (not that I've worked it out ;-)) to leave 10 minutes for the simulation question which I bombed on last time coz I ran out of time. These tables can be written out before the exam clock starts ticking.

If BMoore is interested and still out there the Wendell Odell ICND book in PDF can be found here for download

formatting link
There are no practice questions from the CD or anything else from the CD for that matter, just the PDF (disclaimer - this isn't my site).

K.

# bits mask magic number

1 128 128 2 192 64 3 224 32 4 240 16 5 248 8 6 252 4 7 254 2 8 255 1

I also wrote down multiples of 16 upto 256. ie.

16 32 48 64 96 .. 176 192 208 224 240 256

The reason I wrote down the multiples of 16 was because I found that most 'hard' subnet questions were a .240, /20 or /28 network.

So if you get asked if 192.168.1.239 is a valid host in a /28 network, you can look up and see that 239 is 1 less than 240, so it's a broadcast address.

Or if your asked if 192.168.1.173/28 and 192.168.1.178/28 are in the same subnet, you can see straight away that they are not.

If asked about a .224 or .192 network, then you can just look at every

2nd or 4th number in the list.

Kendo Nagasaki wrote:

Reply to
Kendo Nagasaki

formatting link
I memorized both of those charts for my INTRO Exam and wrote them down before the exam started....

If you can memorize those 2 charts and know binary and how to do the binary AND operation you should not have ANY trouble passing the CCNA INTRO exam.

Reply to
BMoore

Adding in the number of subnets and hosts into the table is a good idea

- I didn't even think of it.

Kendo Nagasaki wrote:

Reply to
Brad

That's a lot to remember!

I had seen these tables before and I can understand the logic behind them. But the magic number table can be applied to any of the octets, instead of remembering a huge table for all of class B and class C. It's also much easier to remember and write down.

How can you work out the subnet address of 192.168.2.67/28 quickly using the class c table?

BMoore wrote:

Reply to
Brad

You do the boolean AND operation

you already know its going to be 192.168.2.*

so you take the binary of /28 which is 11110000 for the last octet then you take the binary of 67 which is 01000011

you do the AND opertaion if their is a 1 and a 1 then it is a 1 if their is a 0 and a 1 then it is a 0 or if its 0 and 0 its 0

so 11110000

  • 01000011

------------------ = 01000000 subnet address = 192.168.2.64

Reply to
BMoore

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