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Posted by on September 23, 2008, 12:52 pm
Please log in for more thread options Hi, I am thinking about extending my wireless coverage by adding a WAP (and a wireless-ethernet bridge) that will be powered by batteries. The wireless-ethernet bridge will be the client feeding the WAP, so the WAP can be run as a complete WAP and not a repeater. The power specs for the bridge and WAP are the same: INPUT: 100 - 120VAC (0.5A) OUTPUT: 5VDC (2.5A) Stupid question: How do you determine how many watts are actually used? Is this simply by multiplying the voltage with the amperage of the output specs? Am I adding this up correctly for a 12V battery? 5V x 2.5A = 12.5W 12W x 2 (devices) = 25W 25W / 12V = ~ 2.10 AaH (Amps per hour) So, say, a 12V 100A (deep cycle) battery should last ~47 hours if supplying 5VDC (2.5A) continuously? (Well, somewhat less, because of inefficiency.) Then, later on, I could double that amount of time by adding a second battery and connecting them in parallel. Am I adding up correctly here? I would, obviously, be using a DC-DC converters in place of the power adapters, not a DC-AC inverter with the power adapters. Thanks! | |||||||||||||||||||||||||
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Posted by DanS on September 23, 2008, 2:52 pm
Please log in for more thread options 34g2000hsh.googlegroups.com: These specs are the for the power adapter, not what the unit actually uses. The only way to know exactly how much is used, is to use a meter and measure it....and that will then only be an average power consumption. The unit uses far less in TX mode than while in RX mode. And yes...power (W) = voltage (V) * current (W) >
> Stupid question: How do you determine how many watts are actually > used? Is this simply by multiplying the voltage with the amperage of > the output specs? > > Am I adding this up correctly for a 12V battery? > > 5V x 2.5A = 12.5W > > 12W x 2 (devices) = 25W > > 25W / 12V = ~ 2.10 AaH (Amps per hour) > > So, say, a 12V 100A (deep cycle) battery should last ~47 hours if > supplying 5VDC (2.5A) continuously? (Well, somewhat less, because of > inefficiency.) > > Then, later on, I could double that amount of time by adding a second > battery and connecting them in parallel. > > Am I adding up correctly here? I would, obviously, be using a DC-DC > converters in place of the power adapters, not a DC-AC inverter with > the power adapters. > > Thanks! > > > > > > > > | |||||||||||||||||||||||||
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Posted by danny burstein on September 23, 2008, 3:04 pm
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>These specs are the for the power adapter, not what the unit actually
>uses. The only way to know exactly how much is used, is to use a meter >and measure it....and that will then only be an average power >consumption. The unit uses far less in TX mode than while in RX mode. Wouldn't it be the other way around? (And does a typical access point "power down" when just sitting there as opposed to actively transferring big data streams? I really don't know...) -- _____________________________________________________ Knowledge may be power, but communications is the key dannyb@panix.com [to foil spammers, my address has been double rot-13 encoded] | |||||||||||||||||||||||||
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Posted by DanS on September 23, 2008, 5:25 pm
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>
>>These specs are the for the power adapter, not what the unit actually
>>uses. The only way to know exactly how much is used, is to use a meter >>and measure it....and that will then only be an average power >>consumption. The unit uses far less in TX mode than while in RX mode. >
> Wouldn't it be the other way around? Uh...yeah....it was a long.....long day. Sorry. Boy did I blow that one. Trying to program rtr's (real rtr's, not consumer gear AP's) that you're not familiar with really strains the brain. That is what I meant...TX is much more DC power than RX....DOH !!!!! You can never go by what the PS says. The PS should always be over-rated for the device....by 50% of the actual current draw, IMO. We've got a 900mhz DSSS radio that comes with a 1.5A 12v PS and is rated @ 700mA (which is ~100% over-rated) @ 12V for a full 1W output. Well I measured it, and in diag keyed mode, as in constant TX, it only uses ~ 400ma @ 12v. | |||||||||||||||||||||||||
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Posted by on September 23, 2008, 5:47 pm
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wrote: > 34g2000hsh.googlegroups.com:
> > > Hi,
>
> > I am thinking about extending my wireless coverage by adding a WAP
> > (and a wireless-ethernet bridge) that will be powered by batteries. >
> > The wireless-ethernet bridge will be the client feeding the WAP, so
> > the WAP can be run as a complete WAP and not a repeater. >
> > The power specs for the bridge and WAP are the same:
>
> > INPUT: 100 - 120VAC =A0(0.5A)
> > OUTPUT: 5VDC (2.5A) >
> These specs are the for the power adapter, not what the unit actually > uses. The only way to know exactly how much is used, is to use a meter > and measure it....and that will then only be an average power > consumption. The unit uses far less in TX mode than while in RX mode. > > And yes...power (W) =3D voltage (V) * current (W) Thanks. That makes sense. I'll go ahead and measure the actual power being used. Jeff straightened me out on the battery. I didn't realize that the battery is only good for the first 25 percent. Ouch! | |||||||||||||||||||||||||
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Calculating power consumption...
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>
> I am thinking about extending my wireless coverage by adding a WAP
> (and a wireless-ethernet bridge) that will be powered by batteries.
>
> The wireless-ethernet bridge will be the client feeding the WAP, so
> the WAP can be run as a complete WAP and not a repeater.
>
> The power specs for the bridge and WAP are the same:
>
> INPUT: 100 - 120VAC (0.5A)
> OUTPUT: 5VDC (2.5A)