AC Adaptor in Parallel With Battery?
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Posted by Paul on April 15, 2008, 7:21 pm
Please log in for more thread options We plan on placing a +12VDC AC adaptor (110-220AC, which will plug into an outlet) in parallel with a battery connector using a "Y" connector, so that the user can operate our device using either a battery, or the wall adaptor. ONLY EITHER the battery or the wall adaptor will be hooked up at any time. Here is the adaptor we will use: http://www.cui.com/pdffiles/DPS120100UPS-P5P-SZ.pdf However, will the impedance of the AC adaptor (when it's not plugged in) be sufficiently high enough to make the current draw on the battery insignificant? Because if the adaptor looks anything like the following: http://www.coilws.com/images/Switch%20Mode/1R5W_ckt.gif Then I'm not worried about the half-wave rectifying diode, but rather the shunt Zener diode which is only 8.2V. I'm hoping that the current draw going into the adaptor will be insignificant, so that i can wire it in parallel to the battery connector, without having to hassle with putting a relay or switch in there. Maybe i can just solder in a series diode in-line with the AC adaptor.... | ||||||||||||||||||||||||||||||||||||||||||||||||||||
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Posted by on April 15, 2008, 8:35 pm
Please log in for more thread options You could have done that in less time than it took to write that post. So what do you think the answer is? | ||||||||||||||||||||||||||||||||||||||||||||||||||||
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Posted by Paul on April 15, 2008, 11:34 pm
Please log in for more thread options On Apr 15, 5:35=EF=BF=BDpm, a7yvm109gf...@netzero.com wrote:
>
> > > > > > =EF=BF=BD =EF=BF=BD =EF=BF=BD =EF=BF=BD =EF=BF=BD We plan on placing a +=
12VDC AC adaptor (110-220AC, which
> > will plug into
> > an outlet) in parallel with a battery connector using a "Y" connector, > > so that the user can operate our device using either a battery, or the > > wall adaptor. =EF=BF=BDONLY EITHER the battery or the wall adaptor will > > be hooked up at any time. >
> > =EF=BF=BD =EF=BF=BD =EF=BF=BD =EF=BF=BD =EF=BF=BD =EF=BF=BDHere is the a=
daptor we will use:
>
> > =EF=BF=BD =EF=BF=BD =EF=BF=BD =EF=BF=BD =EF=BF=BD =EF=BF=BD =EF=BF=BD =
=EF=BF=BDhttp://www.cui.com/pdffiles/DPS120100UPS-P5P-SZ.pdf >
> > =EF=BF=BD =EF=BF=BD =EF=BF=BD =EF=BF=BD =EF=BF=BD =EF=BF=BDHowever, will=
the impedance of the AC adaptor (when it's
> > not plugged in) be sufficiently
> > high enough to make the current draw on the battery insignificant? >
> > =EF=BF=BD =EF=BF=BD =EF=BF=BD =EF=BF=BD =EF=BF=BD =EF=BF=BDBecause if th=
e adaptor looks anything like the following:
>
> > =EF=BF=BD =EF=BF=BD =EF=BF=BD =EF=BF=BD =EF=BF=BD =EF=BF=BDhttp://www.co=
ilws.com/images/Switch%20Mode/1R5W_ckt.gif
>
> > Then I'm not worried about the half-wave rectifying diode, but rather
> > the shunt Zener diode which is only 8.2V. >
> > =EF=BF=BD =EF=BF=BD =EF=BF=BD =EF=BF=BD =EF=BF=BD =EF=BF=BDI'm hoping th=
at the current draw going into the adaptor
> > will
e.
> > be insignificant, so that i can wire it in parallel to the battery > > connector, > > =EF=BF=BDwithout having to hassle with putting a relay or switch in ther= >
> > =EF=BF=BD =EF=BF=BD =EF=BF=BD =EF=BF=BD =EF=BF=BD =EF=BF=BDMaybe i can j=
ust solder in a series diode in-line with the
> > AC adaptor....
>
> You could have done that in less time than it took to write that post. > So what do you think the answer is?- Hide quoted text - > > - Show quoted text - Don't ask advice from a numbskull... | ||||||||||||||||||||||||||||||||||||||||||||||||||||
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Posted by on April 16, 2008, 11:25 am
Please log in for more thread options
> > You could have done that in less time than it took to write that post.
> > So what do you think the answer is?- Hide quoted text - >
> > - Show quoted text -
>
> Don't ask advice from a numbskull... Or respond to questions from one.... Your thick, armor-plated skull is resistant to not only the physical beatings you must endure every day in real life, but to all forms of sense people here are trying to tell you. You are an ignorant fuckwit. You are of the dangerous class of people who are convinced they know everything and therefore don't need to learn anything. The only good thing here is that you are playing with mains voltage, one can only hope that you die a quick, crispy death. | ||||||||||||||||||||||||||||||||||||||||||||||||||||
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Posted by Phil Allison on April 16, 2008, 7:36 pm
Please log in for more thread options
>
> Your thick, armor-plated skull is resistant to not only the physical > beatings you must endure every day in real life, but to all forms of > sense people here are trying to tell you. > > You are an ignorant fuckwit. You are of the dangerous class of people > who are convinced they know everything and therefore don't need to > learn anything. > > The only good thing here is that you are playing with mains voltage, > one can only hope that you die a quick, crispy death. ** Slow and excruciating would be preferable. ...... Phil | ||||||||||||||||||||||||||||||||||||||||||||||||||||
> will plug into
> an outlet) in parallel with a battery connector using a "Y" connector,
> so that the user can operate our device using either a battery, or the
> wall adaptor. ONLY EITHER the battery or the wall adaptor will
> be hooked up at any time.
>
> Here is the adaptor we will use:
>
> http://www.cui.com/pdffiles/DPS120100UPS-P5P-SZ.pdf
>
> However, will the impedance of the AC adaptor (when it's
> not plugged in) be sufficiently
> high enough to make the current draw on the battery insignificant?
>
> Because if the adaptor looks anything like the following:
>
> http://www.coilws.com/images/Switch%20Mode/1R5W_ckt.gif
>
> Then I'm not worried about the half-wave rectifying diode, but rather
> the shunt Zener diode which is only 8.2V.
>
> I'm hoping that the current draw going into the adaptor
> will
> be insignificant, so that i can wire it in parallel to the battery
> connector,
> without having to hassle with putting a relay or switch in there.
>
> Maybe i can just solder in a series diode in-line with the
> AC adaptor....