Difficult to have a clear idea for SFP|
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Posted by Michelot on April 23, 2009, 5:57 am
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Is an SFP can convert a value of a wavelength (at the client sink side) in another value of a wavelength (at the long distance network source side)? Would you have please an example? If this conversion is possible, does the client signal need to pass by the electrical domain, or do we stay at the optical level without going to the electrical domain? Thanks for your words about that. Best regards, Michelot | |||||||||||||
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Posted by Ergyn Sadiku on April 24, 2009, 10:23 am
Please log in for more thread options Hello Michelot, I will now try to explain what transceivers are and how do they work. Transceiver is a contraction of two words "transmitter" and "receiver". Lets talk about the optical receiver first. Signal is received by a photodetector which gives a small amout of current to the output.Current then is amplified and is converted to voltage which should be amplified further by LA (limiting amplifier) which is known as main amplifier. The resulting signal which is several 100mV is put into a clock and data recovery circuit, extraxting the clock signal and re-timing the data signal. In high speed receiver, demultiplexer (DMUX) converts a fast speed data stream to (n)paralel slow speed data stream that can be further processed by digital logic block (DLB). DLB decodes the bits, performs error checks, synchronizes to another clock domain, etc. The same happens with the transmitter but in reverse order. Ergyn Sadiku | |||||||||||||
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Posted by Michelot on April 24, 2009, 3:36 pm
Please log in for more thread options Bonsoir Ergyn,
Thanks for the time you spent in this interresting description. > ... The resulting signal which is several 100mV is put
> into a clock and data recovery circuit, extraxting the clock signal > and re-timing the data signal. In high speed receiver, demultiplexer > (DMUX) converts a fast speed data stream to (n)paralel slow speed data > stream that can be further processed by digital logic block (DLB). DLB > decodes the bits, performs error checks, synchronizes to another clock > domain, etc. Reading another time my question, I realized that it was not really clear (as almost all questions...). In fact we have SFP for many different applications. What you describe could be e.g. what we call 3R regeneration, with the functions: reamplification, reshaping, resynchronization. I saw also that we used SFP to transmit Ethernet frames on TDM circuit networks (E1 at the SFP network side). And in this application, the description you give seems natural (thanks for reminding it). What I had in my brain was a WDM SFP. For example, you receive at the client side a 1310 nm wavelength of an Ethernet signal. To insert the wavelength in a CWDM multiplexing group, you choose an SFP that convert it in a 1491 nm value. To make this conversion, I suppose we have 2 solutions: - either to go through the electrical domain, as you well described it, - either to stand only in the optical domain, using a kind of mirror (I don't know if it is a good word). Thanks for your opinion, best regards, Michelot | |||||||||||||
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Posted by Michelot on April 27, 2009, 11:59 am
Please log in for more thread options Bonjour,
Thanks to Omnicron support, I have the perfect reply to my question. The conversion is not done by going through the electrical domain. "The conversion of wavelengths is done in the optical domain. Using our iConverter xFF module, you can provide a 1310nm interface to the client and convert it to 1491nm for transport on the network side. The only requirement is both interfaces must be the same speed". http://www.omnitron-systems.com/downloads/datasheets/8699DS-C.pdf Thanks to you, this channel and Omnicron support. Best regards, Michelot | |||||||||||||
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>
> Is an SFP can convert a value of a wavelength (at the client sink
> side) in another value of a wavelength (at the long distance network
> source side)?
>
> Would you have please an example?
>
> If this conversion is possible, does the client signal need to pass by
> the electrical domain, or do we stay at the optical level without
> going to the electrical domain?
>
> Thanks for your words about that.
> Best regards,
> Michelot