Bookmark this page:
Yahoo!
Windows Live
del.icio.us
digg
Netscape
|
|
||||||||||||||||||||||||||||
|
Posted by on April 23, 2007, 4:23 pm
Please log in for more thread options I have a very simple electrical question. I have a portable heater which is rated at 12 V, 12.5 amps, which I have attached to a 12 V, 73 amp hour battery. I'm wanting to get a rough idea of how long this heater could run before completely draining the battery. | ||||||||||||||||||||||||||||
|
Posted by Michael A. Terrell on April 23, 2007, 4:27 pm
Please log in for more thread options dmehling@keenebroadband.com wrote: 73/12.5 = ? -- Service to my country? Been there, Done that, and I've got my DD214 to prove it. Member of DAV #85. Michael A. Terrell Central Florida | ||||||||||||||||||||||||||||
|
Posted by Sjouke Burry on April 23, 2007, 7:53 pm
Please log in for more thread options
Michael A. Terrell wrote: > dmehling@keenebroadband.com wrote:
>> I have a very simple electrical question. I have a portable heater
>> which is rated at 12 V, 12.5 amps, which I have attached to a 12 V, 73 >> amp hour battery. I'm wanting to get a rough idea of how long this >> heater could run before completely draining the battery. >
> > 73/12.5 = ? And then assume an efficiency of about 80 percent, so (73/12.5)*.8 | ||||||||||||||||||||||||||||
|
Posted by Phil Allison on April 24, 2007, 1:27 am
Please log in for more thread options
"Sjouke Burry" >
>>> I have a very simple electrical question. I have a portable heater
>>> which is rated at 12 V, 12.5 amps, which I have attached to a 12 V, 73 >>> amp hour battery. I'm wanting to get a rough idea of how long this >>> heater could run before completely draining the battery. >>
>> >> 73/12.5 = ? >
> And then assume an efficiency of about 80 percent, ** So the missing 20% turns into what ? IR light ? Cosmic radiation ? Fairy dust ?? ........ Phil | ||||||||||||||||||||||||||||
|
Posted by Tom Biasi on April 24, 2007, 5:36 am
Please log in for more thread options
>
> "Sjouke Burry" > >>
>>>> I have a very simple electrical question. I have a portable heater
>>>> which is rated at 12 V, 12.5 amps, which I have attached to a 12 V, 73 >>>> amp hour battery. I'm wanting to get a rough idea of how long this >>>> heater could run before completely draining the battery. >>> >>> >>> 73/12.5 = ? >>
>> And then assume an efficiency of about 80 percent, >
> > ** So the missing 20% turns into what ? > > IR light ? > > Cosmic radiation ? > > Fairy dust ?? > > > > > ........ Phil > Heat in the battery and chemical changes and maybe a little fairy dust. | ||||||||||||||||||||||||||||

power consumption for portable heater
Yahoo!
Windows Live
del.icio.us
digg
Netscape 








> I have a very simple electrical question. I have a portable heater
> which is rated at 12 V, 12.5 amps, which I have attached to a 12 V, 73
> amp hour battery. I'm wanting to get a rough idea of how long this
> heater could run before completely draining the battery.