I know the answers are 10.0.152.0/21 and 10.0.160.0/19, but I am a bit confused as to how you work out the problem to find these solutions, especially for the 10.0.160.0/19. Any help is appreciated.
I believe the book is wrong. It is better to understand the concept than blindly believe in the book. The /18 comes from 8+8+2 (8 in the first octet, 8 in the second octet and 2 in the third octet).
"For summarization to work properly, addresses must be carefully assigned in a hierarchical fashion so that summarized addresses share the same high-order bits."
2,3,4,5 and 6 can be summarized to 10.0.160.0/19 range: 10.0.160.0 -=20
10.0.191.255 (the same)
all these networks can be summarized to 10.0.128.0/18 range:=20
10.0.128.0 - 10.0.191.255 but the question is tricky. We have only those network and nothing else - especially networks=20
10.0.128.0 to 10.0.151.0 can be somwhere else.
laugh at yourself. 'cos the answer written in the first post by the original poster has been explained many times now. It's the same answer. so I don't see what you're complaining about.
2,3,4,5 and 6 can be summarized to 10.0.160.0/19 range: 10.0.160.0 -
10.0.191.255 (the same)
all these networks can be summarized to 10.0.128.0/18 range:
10.0.128.0 - 10.0.191.255 but the question is tricky. We have only those network and nothing else - especially networks
10.0.128.0 to 10.0.151.0 can be somwhere else.
So the aswer in the flash cards is OK"
So what I am suggesting is that this appears to be a tricky question, as noted by Ern, and the answer from the uninitiated reading this thread may not be completely clear.
I know the answers are 10.0.152.0/21 and 10.0.160.0/19, but I am a bit confused as to how you work out the problem to find these solutions, especially for the 10.0.160.0/19. Any help is appreciated.
"new guy" schreef in bericht news:4czjg.19488$IK3.8477@pd7tw1no...
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