CIDR question

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If i had a block of two class C address, for example.

192.168.64.0/23 a block size of two class C address's

510 hosts?

Would the broadcast address of this block be 192.168.65.255/23 ?

TIA

Re: CIDR question

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Yes


Yes, the nine host bits are all 1s.

Aubrey



Re: CIDR question
Aubrey Adams wrote:
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ok thanks all. :-)

Re: CIDR question

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yes



Re: CIDR question

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/23 = 255. 255. 254 (7+1).0
Bits left for hosts are 8+1 = 9
2^9=512  or 510 usable hosts

eager and beaver
a.k.a master of subnets



Re: CIDR question
On Tue, 24 Oct 2006 18:12:45 +0000, Jed wrote:

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Class C address starts at /24 and can not be a /23.


Here are some helpful links.

http://www.subnet-calculator.com /

http://www.learntosubnet.com /

Re: CIDR question

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The question is about classless addressing (CIDR/VLSM) so the 2 contiguous
"Class C" networks are summarised/supernetted with a /23 prefix.

IPv4 Classful addressing/routing is a legacy approach these days and will
eventually become a historical footnote (except when configuring EIGRP and
you have remember "no auto-summary").



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